0.6x^2-12x-180=0

Solution for 0.6x^2-12x-180=0 equation:

0.6x^2-12x-180=0

a = 0.6; b = -12; c = -180;
Δ = b2-4ac
Δ = -122-4·0.6·(-180)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*0.6}=\frac{-12}{1.2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*0.6}=\frac{36}{1.2}
=30
$